5u^2-19u+12=0

Solution for 5u^2-19u+12=0 equation:

Simplifying
5u2 + -19u + 12 = 0

Reorder the terms:
12 + -19u + 5u2 = 0

Solving
12 + -19u + 5u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(4 + -5u)(3 + -1u) = 0

Subproblem 1
Set the factor '(4 + -5u)' equal to zero and attempt to solve:

Simplifying
4 + -5u = 0

Solving
4 + -5u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -5u = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5u = 0 + -4
-5u = 0 + -4

Combine like terms: 0 + -4 = -4
-5u = -4

Divide each side by '-5'.
u = 0.8

Simplifying
u = 0.8
Subproblem 2
Set the factor '(3 + -1u)' equal to zero and attempt to solve:

Simplifying
3 + -1u = 0

Solving
3 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1u = 0 + -3
-1u = 0 + -3

Combine like terms: 0 + -3 = -3
-1u = -3

Divide each side by '-1'.
u = 3

Simplifying
u = 3
Solution
u = {0.8, 3}